Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1042: 38

Answer

$ v_{23}=c$

Work Step by Step

We know that $v_{23}=\frac{v_{21}+v_{13}}{1+\frac{v_{21}v_{13}}{c^2}}$ We plug in the known values to obtain: $v_{23}=\frac{0.7c+c}{1+\frac{(0.7c) c}{c^2}}$ $\implies v_{23}=\frac{1.7c}{1+0.7}$ $\implies v_{23}=c$
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