Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1042: 36

Answer

$0.917c$

Work Step by Step

We know that $v=\frac{v_1+v_2}{1+\frac{v_1v_2}{c^2}}$ We plug in the known values to obtain: $v=\frac{0.90c+0.10c}{1+\frac{(0.90c)(0.10c)}{c^2}}$ This simplifies to: $v=0.917c$
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