Answer
(a) $58.0^{\circ}$
(b) $593W/m^2$
Work Step by Step
(a) We can find the required angle as
$\theta_1=cos^{-1}\sqrt{\frac{I_1}{I_{\circ}}}$
We plug in the known values to obtain:
$\theta_1=cos^{-1}\sqrt{232}{825}$
$\theta_1=58.0^{\circ}$
(b) We can find the required intensity as
$I_2=I_{\circ}cos^2({90^{\circ}-\theta_1})$
We plug in the known values to obtain:
$I_2=(825)cos^2(90^{\circ}-58.0^{\circ})$
$I_2=593W/m^2$
