Answer
$15.6W$
Work Step by Step
We can find the average total power as
$P=I(4\pi r^2)$
We plug in the known values to obtain:
$P_{avg}=(3.00\times 10^8)(8.85\times 10^{-12})(16.0)^2 4\pi(135)^2$
$P_{avg}=15.6W$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 905: 102
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