Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 905: 105

Answer

$40m^2$

Work Step by Step

We know that $P=\frac{E}{t}$ We plug in the known values to obtain: $P=\frac{2.00\times 10^3}{25(8h/d)}=10KW$ Now $A=\frac{P}{0.25I}$ We plug in the known values to obtain: $A=\frac{10KW}{0.25(1.00)}=40m^2$
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