Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 905: 106

Answer

$3.85\times 10^{26}W$

Work Step by Step

We know that $P=I(4\pi r^2)$ We plug in the known values to obtain: $P=(1360)4\pi(1.50\times 10^{11})^2$ $P=3.85\times 10^{26}W$
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