Answer
$4.945\times 10^{14}Hz$
Work Step by Step
As $f^{\prime}=f(1-\frac{u}{c})$
We plug in the known values to obtain:
$f^{\prime}=5.00\times 10^{14}(1-\frac{3325\times 10^3}{3.00\times 10^8})$
$f^{\prime}=4.945\times 10^{14}Hz$
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