Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 901: 31

Answer

$\lambda=1.62m$

Work Step by Step

Velocity, wavelength, and frequency are related using the formula $$v=f\lambda$$ Solving for wavelength $\lambda$ yields $$\lambda=\frac{v}{f}$$ Substituting known values of $f=1.75\times 10^8Hz$ and $v=c=3.00\times 10^8m/s$ yields a wavelength of $$\lambda=\frac{3.00\times 10^8m/s}{1.75\times 10^8Hz}=1.62m$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.