Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 901: 27

Answer

$f=1.0\times 10^{18}Hz$

Work Step by Step

Velocity, wavelength, and frequency of a wave are related using the formula $$v=f\lambda$$ Solving for the frequency yields $$f=\frac{v}{\lambda}$$ Substituting known values of $v=c=3.0\times 10^8m/s$ and $\lambda=0.30nm=0.30\times 10^{-9}m$ yields a frequency of $$f=\frac{3.0\times 10^8m/s}{0.30\times 10^{-9}m}$$ $$=1.0\times 10^{18}Hz$$
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