Answer
$3.00\times 10^8\frac{m}{s}$
Work Step by Step
We know that
$c=\frac{2d\omega}{\Delta \theta}$
We plug in the known values to obtain:
$c=\frac{2(35.5\times 10^3)(528)}{\frac{1}{8}rev}$
$\implies c=3.00\times 10^8\frac{m}{s}$
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