Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 871: 80

$127mA$

We know that $C_{eq}=()^{-1}=(\frac{1}{4.40}+\frac{1}{8.80})^{-1}=2.933\mu F$ Now $X_c=\frac{1}{2\pi fC}=\frac{1}{2\pi(60.0)(2.933)}=904.3\Omega$ Now we can find the rms current supplied by the generator as: $I_{rms}=\frac{V_{rms}}{X_c}$ We plug in the known values to obtain: $I_{rms}=\frac{115}{904.3}=127mA$