Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 871: 81

Answer

$66.3\Omega$

Work Step by Step

We know that $C_{eq}=C_1+C_2=(10+30)\times 10^{-6}=40\times 10^{-6}$ Now $X_{c}=\frac{1}{2\pi(f)(C)}$ We plug in the known values to obtain: $X_c=\frac{1}{2\pi(60)(40\times 10^{-6})}$ $X_c=66.3\Omega$
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