Answer
$66.3\Omega$
Work Step by Step
We know that
$C_{eq}=C_1+C_2=(10+30)\times 10^{-6}=40\times 10^{-6}$
Now $X_{c}=\frac{1}{2\pi(f)(C)}$
We plug in the known values to obtain:
$X_c=\frac{1}{2\pi(60)(40\times 10^{-6})}$
$X_c=66.3\Omega$
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