Answer
$572mA$
Work Step by Step
We know that
$C_{eq}=C_1+C_2=4.40+8.80=13.20\mu F$
Now $X_c=\frac{1}{2\pi f C}$
$\implies X_c=\frac{1}{2\pi(60.0)(13.20)}=2.01\Omega$
We can find the rms current supplied by the generator as
$I_{rms}=\frac{V_{rms}}{X_c}$
$I_{rms}=\frac{115}{201}=572mA$
