Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 870: 73

Answer

$27mJ$

Work Step by Step

We are given that the total energy stored in the circuit is $36mJ$. If the current in the inductor becomes half its previous value, then the maximum value of energy in the inductor becomes one fourth (that is, $9.0mJ).$ Hence, the remaining energy in the capacitor is: $36-9.0=27mJ$.
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