Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 870: 62

Answer

$94\mu H$

Work Step by Step

We know that $L=\frac{1}{(2\pi f)^2C}$ We plug in the known values to obtain: $L=\frac{1}{(2\pi (2.4))^2(47\mu F)}$ $L=94\mu H$
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