Answer
(a) $44.52Hz$
(b) $44.52Hz$
Work Step by Step
(a) We can find the required frequency as follows:
$f_{\circ}=\frac{1}{2\pi \sqrt{LC}}$
We plug in the known values to obtain:
$f_{\circ}=\frac{1}{\sqrt{(67.6\times 10^{-3}H)(189\times 10^{-6}F)}}$
$\implies f_{\circ}=44.52Hz$
(b) We can find the required frequency as follows:
$f=\frac{1}{2\pi \sqrt{(67.6\times 10^{-3}H)(189\times 10^{-6}F)}}$
This simplifies to:
$f=44.52Hz$
