Answer
(a) $152.5Hz$
(b) $152.5Hz$
Work Step by Step
(a) We can find the required frequency as
$f=\frac{1}{2\pi \sqrt{LC}}$
We plug in the known values to obtain:
$f=\frac{1}{2\pi \sqrt{(33\times 10^{-6}F)(33\times 10^{-3}H)}}$
$\implies f=152.5Hz$
(b) The resonance frequency can be determined as
$f_{\circ}=\frac{1}{2\pi \sqrt{(33times 10^{-6}F)(33\times 10^{-3}H)}}$
$f_{\circ}=152.5Hz$
