Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 831: 48

Answer

$470\space turns$

Work Step by Step

We can find the number of turns as follows: $N=\sqrt{\frac{lL}{\mu_{\circ}A}}$ We plug in the known values to obtain: $N=\sqrt{\frac{(0.22)(45\times 10^{-3})}{(4\pi\times 10^{-7})(0.035)}}$ $N=470\space turns$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.