Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 831: 44

$17mV$

We know that $N=\frac{L}{C}=\frac{L}{2\pi r}$ $\implies N=\frac{1.6}{(2)(0.032)\pi}$ $N=8$ Now $\epsilon_{max}=NAB\omega$ We plug in the known values to obtain: $\epsilon_{max}=\pi(8)(0.075)(0.032)^2(85rev/min)(\frac{2\pi rad}{rev})(\frac{1min}{60})$ $\epsilon_{max}=17mV$