Answer
(a) $0.65A$
(b) $4.8\frac{m}{s}$
Work Step by Step
(a) We know that
$I=\sqrt{\frac{P}{R}}$
We plug in the known values to obtain:
$I=\sqrt{\frac{5.0}{12}}$
$I=0.65A$
(b) As $v=\frac{IR}{BL}$
We plug in the known values to obtain:
$v=\frac{(1.0)(12)}{(2.0)(1.25)}$
$v=4.8\frac{m}{s}$