Answer
(a) $52.3mN$
(b) $0.300W$
(c) $0.300W$
Work Step by Step
(a) We know that
$F=IBl$
We plug in the known values to obtain:
$F=(0.155)(0.750)(0.450)$
$F=52.3mN$
(b) As $P=I^2R$
We plug in the known values to obtain:
$P=(0.155)^2(12.5)$
$P=0.300W$
(c) We know that
$P=Fv$
We plug in the known values to obtain:
$P=(52.3mN)(5.75\frac{m}{s})$
$P=0.300W$
