Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 794: 39

Answer

$3.5A$

Work Step by Step

We can find the current as follows: $I=\frac{\tau}{NABsin\theta}$ We plug in the known values to obtain: $I=\frac{23}{(260)(0.33)(0.16)(0.48)(1)}$ $I=3.5A$
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