Answer
$F=2.6N$
As the wires attract, the direction of force is towards each other.
Work Step by Step
We know that
$F=\frac{\mu_{\circ}I_1I_2}{2\pi d}L$
We plug in the known values to obtain:
$F=\frac{(4\pi\times 10^{-7})(110)^2}{2\pi(0.25)}\times (270)$
$F=2.6N$
As the wires attract, the direction of force is towards each other.
