Answer
$60^{\circ}$
Work Step by Step
We can find the required angle as follows:
$\tau=NABIsin\theta$
This can be rearranged as:
$\theta=sin^{-1}(\frac{\tau}{NABI})$
We plug in the known values to obtain:
$\theta=sin^{-1}(\frac{0.205N.m}{(1)\pi(0.23m)^2(0.95T)(2.6A)})$
$\theta=sin^{-1}(0.4994)$
$\theta=30^{\circ}$
Now the angle the plane of the loop makes with field is $90^{\circ}-30^{\circ}=60^{\circ}$
