Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 718: 18

Answer

(a) $2.29\times 10^5\frac{m}{s}$ (b) $9.83\times 10^6\frac{m}{s}$

Work Step by Step

(a) We know that $v=\sqrt{\frac{2e\Delta V}{m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{2(1.6\times 10^{-19})(275)}{1.673\times 10^{-27}}}=2.29\times 10^5\frac{m}{s}$ (b) We know that $v=\sqrt{\frac{2e\Delta V}{m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{2(1.6\times 10^{-19})(275)}{9.11\times 10^{-31}\times 10^{-27}}}=9.83\times 10^6\frac{m}{s}$
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