Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 718: 27

Answer

(a) $-2.2\times 10^4V$ (b) $-2.2\times 10^4V$ (c) $-1.5\times 10^4V$

Work Step by Step

(a) We know that $V=\frac{kq}{r}$ We plug in the known values to obtain: $V=\frac{8.99\times 10^9(-7.2\times 10^{-6})}{3.0}$ $V=-2.2\times 10^4V$ (b) We know that $V=\frac{kq}{r}$ We plug in the known values to obtain: $V=\frac{8.99\times 10^9(-7.2\times 10^{-6})}{3.0}$ $V=-2.2\times 10^4V$ (c) We know that $V=\frac{kq}{r}$ We plug in the known values to obtain: $V=\frac{8.99\times 10^9(-7.2\times 10^{-6})}{\sqrt{(3.0)^2+(-3.0)^2}}$ $V=-1.5\times 10^4V$
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