Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 718: 26

Answer

$3.4\mu C$

Work Step by Step

As we know that $V=\frac{Kq}{r}$ This can be rearranged as: $q=\frac{rV}{K}$ We plug in the known values to obtain: $q=\frac{1.1(2.8\times 10^4)}{8.99\times 10^9}$ $q=3.4\times 10^{-6}C=3.4\mu C$
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