Answer
$3.4\mu C$
Work Step by Step
As we know that
$V=\frac{Kq}{r}$
This can be rearranged as:
$q=\frac{rV}{K}$
We plug in the known values to obtain:
$q=\frac{1.1(2.8\times 10^4)}{8.99\times 10^9}$
$q=3.4\times 10^{-6}C=3.4\mu C$
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