Answer
Increase of: $0.56~L$
Work Step by Step
We can find the required volume as
$PV=nRT$
$\implies P(4.1)=nR\times 273$
and $P(v^{\prime})=nR\times 310$
Solving these two equation, we obtain:
$V^{\prime}=\frac{4.1\times 310}{273}$
$V^{\prime}=4.66L$
Which is an increase of $4.66-4.1=0.56~L$
