Answer
(a) faster
(b) $38rev/min$
Work Step by Step
(a) We know that the turntable will rotate faster because the moment of inertia decreases.
(b) The angular speed can be calculated as
$\omega_f=(\frac{I_i}{I_f})\omega_i$
$\omega_f=(\frac{I+mr^2}{I+0})\omega_i$
$\omega_f=\frac{5.4\times 10^{-3}+(0.032)(0.15)^2}{5.4\times 10^{-3}}(33\frac{1}{3}rev/min)$
$\omega_f=38rev/min$
