Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 370: 71

$0.37\frac{rad}{s}$

We know that in the given scenario $L_i=L_f$ $mvr+0=I_f\omega_f$ $\implies mvr=(I_{student-stool}+mr^2)\omega_f$ This can be rearranged as: $\omega _f=\frac{mvr}{I_{student-stool}+mr^2}$ We plug in the known values to obtain: $\omega_f=\frac{(1.5)(2.7)(0.40)}{(4.1)+(1.5)(0.40)^2}$ $\omega_f=0.37\frac{rad}{s}$