Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 370: 60

Answer

$0.20KN.m$

Work Step by Step

We know that $\tau=\frac{L_2-L_1}{\Delta t}$ We plug in the known values to obtain: $\tau=\frac{9700-8500}{5.86}$ $\tau=200N.m$ $\tau=0.20KN.m$
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