Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 33 - Electromagnetic Induction - Exercises and Problems - Page 998: 25

Answer

$R = 750~\Omega$

Work Step by Step

We can find the equivalent resistance $R_{eq}$: $\tau = \frac{L}{R_{eq}}$ $R_{eq} = \frac{L}{\tau}$ $R_{eq} = \frac{7.5\times 10^{-3}~H}{25\times 10^{-6}~s}$ $R_{eq} = 300~\Omega$ We can find $R$: $\frac{1}{R_{eq}} = \frac{1}{500~\Omega}+\frac{1}{R}$ $\frac{1}{R} = \frac{1}{R_{eq}} - \frac{1}{500~\Omega}$ $\frac{1}{R} = \frac{1}{300~\Omega} - \frac{1}{500~\Omega}$ $\frac{1}{R} = \frac{5}{1500~\Omega} - \frac{3}{1500~\Omega}$ $\frac{1}{R} = \frac{2}{1500~\Omega}$ $R = \frac{1500~\Omega}{2}$ $R = 750~\Omega$
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