Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 916: 28

Answer

$\tau = 2ms = 2*10^ {-3 }s$

Work Step by Step

capacitors are in parallel therefore equivalent capacitance $C_{eq} =2\mu F +2\mu F = 4 \mu F $ resistors are in parallel therefore equivalent resistance $\frac{1}{R_{eq}} = \frac{1}{1k\Omega}+ \frac{1}{1k\Omega}$ $R_{eq} =0.5 k\Omega$ Time constant $\tau = R_{eq}*C_{eq} =4\mu F * 0.5 k\Omega$ $\tau = 2ms = 2*10^ {-3 }s$
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