Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 916: 19

Answer

$R = 240~\Omega$

Work Step by Step

We can find the value of $R$: $\frac{1}{75~\Omega} = \frac{1}{200~\Omega}+\frac{1}{R}+\frac{1}{R}$ $\frac{1}{75~\Omega} - \frac{1}{200~\Omega} = \frac{1}{R}+\frac{1}{R}$ $\frac{8}{600~\Omega} - \frac{3}{600~\Omega} = \frac{2}{R}$ $\frac{5}{600~\Omega} = \frac{2}{R}$ $\frac{R}{2} = \frac{600~\Omega}{5}$ $R = 240~\Omega$
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