Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 916: 24

Answer

The equivalent resistance between points a and b is $54.5~\Omega$

Work Step by Step

We can find the equivalent resistance of the three $100~\Omega$ resistors in series: $100~\Omega + 100~\Omega + 100~\Omega = 300~\Omega$ We can find the equivalent resistance of the two $100~\Omega$ resistors in series: $100~\Omega + 100~\Omega = 200~\Omega$ We can find the equivalent resistance of the three values in parallel: $\frac{1}{R} = \frac{1}{100~\Omega} + \frac{1}{200~\Omega} + \frac{1}{300~\Omega}$ $\frac{1}{R} = \frac{6}{600~\Omega} + \frac{3}{600~\Omega} + \frac{2}{600~\Omega}$ $\frac{1}{R} = \frac{11}{600~\Omega}$ $R = \frac{600~\Omega}{11}$ $R = 54.5~\Omega$ The equivalent resistance between points a and b is $54.5~\Omega$
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