Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 30 - Current and Resistance - Exercises and Problems - Page 888: 46

Answer

$3.24\times 10^5\;\rm C$

Work Step by Step

We know that the current is given by $$I=\dfrac{Q}{t}$$ So the charge amount is given by $$Q=It$$ Plug the known; $$Q=(90)(3600)$$ $$Q=\color{red}{\bf 3.24\times 10^5}\;\rm C$$
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