Answer
$1.38\;\rm \Omega\cdot m$
Work Step by Step
According to Ohm’s law,
$$\Delta V=IR$$
where $R=\dfrac{\rho L}{A}$
$$\Delta V=I\dfrac{\rho L}{A}$$
Solving for the resistivity;
$$\rho=\dfrac{A\Delta V }{I L}=\dfrac{\pi r^2 \Delta V }{I L}$$
Plug the known;
$$\rho =\dfrac{\pi (0.75\times 10^{-3})^2 (9) }{(230\times 10^{-6})(5\times 10^{-2})}$$
$$\rho=\color{red}{\bf 1.38}\;\Omega\cdot m$$
