Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 651: 55

Answer

$\lambda = 667~nm$

Work Step by Step

We can find the wavelength of the light: $w = \frac{2~\lambda~L}{a}$ $\lambda = \frac{w~a}{2~L}$ $\lambda = \frac{(0.010~m)(0.20\times 10^{-3}~m)}{(2)~(1.5~m)}$ $\lambda = 6.67\times 10^{-7}~m$ $\lambda = 667~nm$
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