Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 651: 57

Answer

$D = 0.12~mm$

Work Step by Step

We can find the diameter of the aperture: $w = \frac{2.44~\lambda~L}{D}$ $D = \frac{2.44~\lambda~L}{w}$ $D = \frac{(2.44)(500\times 10^{-9}~m)(1.0~m)}{0.010~m}$ $D = 1.2\times 10^{-4}~m$ $D = 0.12~mm$
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