Answer
(a) We can let $~~550~nm~~$ be the average wavelength of the sunlight.
(b) $D = 0.4~mm$
Work Step by Step
(a) Visible light has wavelengths in the range of approximately $400~nm$ to $700~nm$
We can let $~~550~nm~~$ be the average wavelength of the sunlight.
(b) We can find the diameter of the aperture:
$w = \frac{2.44~\lambda~L}{D}$
$D = \frac{2.44~\lambda~L}{w}$
$D = \frac{(2.44)(550\times 10^{-9}~m)(3.0~m)}{0.010~m}$
$D = 4\times 10^{-4}~m$
$D = 0.4~mm$
