Answer
$16^\circ$
Work Step by Step
We know, in a diffraction grating, that the angle of a bright fringe is given by
$$d\sin\theta_m=m\lambda$$
So, the first-order diffraction angle is at $m=1$. Hence,
$$d\sin\theta_1= \lambda$$
$$\theta_1=\sin^{-1}\left[ \dfrac{\lambda}{d} \right]$$
Plugging the known;
$$\theta_1=\sin^{-1}\left[ \dfrac{550\times 10^{-9}}{2\times 10^{-6}} \right]$$
$$\theta_1=\color{red}{\bf 16^\circ}$$