Answer
$0.023Pa$
Work Step by Step
The required pressure can be determined as follows:
$p=\frac{k_b T}{4\sqrt{2}\pi r^2 \lambda}$
We plug in the known values to obtain:
$p=\frac{1.38\times 10^{-23}\times 293}{4\sqrt{2}\pi (10^{-6})^2\times 1}$
This simplifies to:
$p=0.023Pa$
