Answer
$2.69\times 10^{25}\frac{1}{m^3}$
Work Step by Step
We can calculate the required number density as follows:
$\frac{N}{V}=\frac{p}{K_bT}$
We plug in the known values to obtain:
$\frac{N}{V}=\frac{1.013\times 10^5}{1.38\times 10^{-23}\times 273}$
This simplifies to:
$\frac{N}{V}=2.69\times 10^{25}\frac{1}{m^3}$
