Answer
See the detailed answer below.
Work Step by Step
a) A sample of 0.12 g of an ideal gas that has an atomic mass of 20 u. Its initial pressure is 2 atm and its initial volume is 100 cm$^3$ find its temperature. And if you know that this sample goes under an isobaric process that makes its final pressure is 200 cm$^3$, what its final temperature?
c) The initial temperature is given by
$$T_1=\dfrac{(2\times 101,300)(100\times 10^{-6})}{n(8.31)}$$
so, we can use the second given formula to find $n=0.12/20$
$$T_1=\dfrac{(2\times 101,300)(100\times 10^{-6})}{(\frac{0.12}{20})(8.31)}$$
$$T_1=\color{red}{\bf 406}\;\rm K$$
Thus, the final temperature is given by
$$T_2=\dfrac{200}{100}\times 406$$
$$T_2=\color{red}{\bf 812}\;\rm K$$
b) We have 2 points here,
$\rm ( 100\;cm^3,2\;atm )$
$\rm ( 200\;cm^3,2\;atm )$
See the figure below.
