Answer
$606C^{\circ}$
Work Step by Step
We can find the temperature $T_2$ as follows:
$\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}$
$\implies \frac{p_1V_1}{T_1}=\frac{3p_1\cdot 3V_1}{T_2}$
This can be rearranged as:
$T_2=9T_1$
We plug in the known values to obtain:
$T_2=9(293)$
$\implies T_2=879K=606C^{\circ}$
