Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 467: 71

Answer

$93cm^3$

Work Step by Step

We can find the required volume as follows: $V^{\prime}=\frac{pMV}{\rho RT}$ We plug in the known values to obtain: $V^{\prime}=\frac{(20)(101300)(0.018)(10,000)}{1000(8.31)(273+200)}$ This simplifies to: $V^{\prime}=93cm^3$
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