Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 17 - Waves-II - Problems - Page 509: 51

Answer

$T=2.25ms$

Work Step by Step

The difference between two slightly different frequencies is known as the number of beats. Mathematically, $f_1-f_2=No.of beats$ putting the values $f_1-440=4$ But we know that by definition $f=\frac{1}{T}$ thus $\frac{1}{T}-440=4$ $\frac{1}{T}=4+440=444$ $T=\frac{1}{444}$ $T=0.00225s=2.25\times10^{-3}s=2.25ms$ $T=2.25ms$
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