Answer
The tension in the wire is $~~64.8~N$
Work Step by Step
In part (a), we found that $f = 71.5~Hz$
We can find the wave speed along the string:
$v = \lambda~f$
$v = 2L~f$
$v = (2)(0.330~m)(71.5~Hz)$
$v = 47.19~m/s$
We can find the tension in the wire:
$v = \sqrt{\frac{\tau}{\mu}}$
$v^2 = \frac{\tau}{\mu}$
$\tau = v^2~\mu$
$\tau = (47.19~m/s)^2~(0.00960~kg/0.330~m)$
$\tau = 64.8~N$
The tension in the wire is $~~64.8~N$
