Answer
The length of pipe B is $~~0.715~m$
Work Step by Step
The second harmonic of pipe A has a frequency of $600~Hz$
We can find the length of pipe B:
$f = \frac{5v}{4L}$
$L = \frac{5v}{4f}$
$L = \frac{(5)(343~m/s)}{(4)(600~Hz)}$
$L = 0.715~m$
The length of pipe B is $~~0.715~m$
