Answer
$v=405\frac{m}{s}$
Work Step by Step
In the given scenario, $\lambda=2L$
We know that, $v=f\lambda$.
Therefore;
$v=f2L$
We plug in the known values to obtain:
$v=2(0.22)(920)=405\frac{m}{s}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 17 - Waves-II - Problems - Page 508: 39a
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